Question
Determine the smallest 4-digit number that, when divided
by 15, 24, and 30, leaves a remainder of 5 each time.Solution
Prime factorization of 15 = 3 1 X 5 1 Prime factorization of 24 = 2 3 X 3 1 Prime factorization of 30 = 2 1 X 3 1 X 5 1 LCM of (15, 24, and 30) = 2 3 X 3 1 X 5 1 = 8 X 3 X 5 = 120 Least 4-digit number divisible by 120 = 1,080 So, required number = 1080 + 5 = 1,085
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Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation.
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X and –
64 + 15 ÷ 90 - 120 X 17
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If 'A' means '×', 'B' means '÷', 'C' means '+', and 'D' means '-', then what will come in the place of '?' in the given expression?
180 A 5 ...
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Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation.
[(345 + 255) ÷ 30 X 12 ...
