Question
In an examination, five students—A, B, C, D, and
E—participated. The overall average score for these students was 58. Specifically, students A, C, and D together had an average score of 55. Moreover, student E scored 33 marks higher than student B. Calculate the marks obtained by student B.Solution
Sum of marks scored by 'A', 'B', 'C', 'D' and 'E' = 58 X 5 = 290 Sum of marks scored by 'A'. 'C' and 'D' = 55 X 3 = 165 So, sum of marks scored by 'B' and 'E' = 290 - 165 = 125 Let the marks scored by 'B' = 'x' Then, marks scored by 'E' = (x + 33) We have, x + x + 33 = 2x + 33 = 125 So, x = (125 - 33) Ă· 2 = 46 Hence, option d.
Find the wrong number in the given number series.
121, 132, 145, 160, 181, 204
15, 30, 30, 20, 10, 8
Find the wrong number, in the given number series,
24, 48, 88, 144, 224, 304
Find the Wrong number in the given number series.
3, 6, 2, 8, 2.4, 9.6
Find the wrong number in given number series.
1687, 1666, 1618, 1549, 1457, 1342.
- Find the wrong number in the given number series.
50, 64, 90, 134, 190, 260 Find the wrong number in the given number series.
11, 30, 67, 133, 219, 346
23, 36, 53, 69, 95, 124, 155
7, 16, 33, 74, 153, 312
5 4 15 36 107 226
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