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    Question

    How many values of 'k' ('k' is a natural number) are

    possible if '7854k8' is always divisible by 8?
    A 4 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    D 3 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 8 when last three digits of number is divisible by 8.
    '4k8' is divisible by 8 when 'k' = 0, 4 and 8
    But 0 is not a natural number. So, there are 2 possible values of 'k'.

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