Question
How many values of 'k' ('k' is a natural number) are
possible if '7854k8' is always divisible by 8?Solution
A number is divisible by 8 when last three digits of number is divisible by 8.
'4k8' is divisible by 8 when 'k' = 0, 4 and 8
But 0 is not a natural number. So, there are 2 possible values of 'k'.
169, 224, 293, 385, 497, 629
Find the wrong number in the given number series.
20, 33, 50, 69, 93, 121
25Â Â Â 26Â Â Â Â 28Â Â Â Â 32Â Â Â Â 42Â Â Â Â 56
Find the wrong number in the given number series.
8, 12, 23, 40, 66, 103
8137, 5405, 3669, 2701, 2201, 1997
Find the wrong number in the given number series.
78, 66, 51, 39, 20, 12
2824Â Â Â Â 2314Â Â Â Â Â 1973Â Â Â Â 1759Â Â Â Â 1634Â Â Â Â 1574
In each of the following number series, one term is wrong. Find the wrong term.
3, 7, 13, 21, 31, 42, 57
Find the wrong term in the given series below.
2847, 2954, 2799, 3088, 2727, 3256
Find the wrong number in the given number series.
2, 5, 10, 17, 26, 38, 50
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