Question
Find the least number to be added to the largest 3-digit
number which leaves remainder 6 when divided by 4, 5, and 7 so that the result becomes a perfect square.Solution
ATQ,
LCM (4, 5, 7) = 140
140 × 7 = 980
N = 980 + 6 = 986
Next perfect square = 32² = 1024
Required number = 1024 - 986 = 38
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