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    Question

    Find the least number to be added to the largest 3-digit

    number which leaves remainder 6 when divided by 4, 5, and 7 so that the result becomes a perfect square.
    A 49 Correct Answer Incorrect Answer
    B 38 Correct Answer Incorrect Answer
    C 25 Correct Answer Incorrect Answer
    D 56 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM (4, 5, 7) = 140

    140 × 7 = 980

    N = 980 + 6 = 986

    Next perfect square = 32² = 1024

    Required number = 1024 - 986 = 38

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