Question
If 893x2 is divisible by 56, and x > 6, find
x.Solution
ATQ,
Divisibility by 8: The last three digits of 893x2 are 3x2, which is 302+10x. Check values of x: For x=7: 372÷8=46.5 (not divisible) For x=8: 382÷8=47.75 (not divisible) For x=9: 392÷8=49 (divisible) Divisibility by 7: Check if 89392 is divisible by 7: 89392÷7=12770.2857(not divisible) Conclusion: No value of x>6 makes 893x2 divisible by both 7 and 8.
Consider the following C++ code:
  int a = 5;
  int b = 10;
  if (a > 0 && b < 10) {
    a = a + b;
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