Question
A number gives a remainder of 14 when divided by 29. What
will be the remainder when six times that number is divided by 29?Solution
ATQ,
Number = (29A + 14), where 'A' is a constant.
Therefore, required remainder = [6 × (29A + 14)] ÷ 29
= (174A + 84) ÷ 29
= (174A + 58 + 26) ÷ 29 = 26
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