What is the highest possible sum of (p + q) if the

Solution

ATQ,

A number is divisible by 12 if it is divisible by both 3 and 4.

A number is divisible by 4 when the last two digits of the number are divisible by 4.

'q3' is divisible by 4 when 'q' = 0, 2, 4, 6, or 8.

Since we have to find the maximum value, so 'q' = 8.

A number is divisible by 3 when the sum of its digits is divisible by 3.

So, (4 + p + 6 + 7 + 9 + 8 + 3) = (37 + p) must be divisible by 3.

So, 'p' = 2, 5, or 8.

Since we have to find the maximum value, so 'p' = 8.

Therefore, required value = 8 + 8 = 16 .