Question
Sum of squares of three consecutive numbers is 1454.
Find the sum of first and third number.Solution
Let the numbers be (x – 1), x and (x + 1) => (x – 1)2 + x2 + (x + 1)2 = 1454 => x2 – 2x + 1 + x2 + x2 + 2x + 1 = 1454 => 3x2 = 1454 - 2 => x2 = 1452/3 => x2 = 484 => x = 22 Required sum = (22 – 1) + (22 + 1) = 44
Select the number that will replace the question mark (?) in the following series.
35, 38, 43, 50, 61, 74, ?
Select the number from among the given option that can replace the question mark (?) in the following series.
11, 18, 30, 52, 94, ?
Find the missing number.
- Study the given pattern carefully and select the number that can replace the question mark [?] in it.
First row: 11, 7, 1274
Second row: 9, ... Study the given pattern carefully and select the number that can replace the question mark [?] in it.
First row: 6, 5, 191
Second row: 9, ...
Find the missing number by analysing the pattern followed by the numbers in each row.
Select the related number from the given alternatives.
29 : 65 : : 43 : ?
What will come in the place of question mark?
E/M ∶ 20/156: : G/O: ?
C/JQ : B/GT : : Z/CX : ?
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