Question
'x' varies directly as per 'y' and 'z'. When 'y' = 6 and
'z' = 8, then x = 16. Find the value of 'z', when 'y' = 8 and x = 24.Solution
Let x = kyz, where 'k' is some constant.
ATQ;
16 = k X 6 X 8
Or, k = (1/3)
So, required value = 24 = (1/3) X z X 8
Or, z = 9
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