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    Question

    There are two natural numbers such that the square of

    the smaller number exceeds five times the larger number by 4. Additionally, the sum of these two numbers is 20. Find the product of these two numbers.
    A 75 Correct Answer Incorrect Answer
    B 84 Correct Answer Incorrect Answer
    C 96 Correct Answer Incorrect Answer
    D 99 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the smaller number be 'a' and larger number be 'b'. a + b = 20 -------- (I) And, a2┬а= 5b + 4 Or, a2┬а= 5 X (20 - a) + 4 (from equation I) Or, a2┬а= 100 - 5a + 4 Or, a2┬а+ 5a - 104 = 0 Or, a2┬а+ 13a - 8a - 104 = 0 Or, a(a + 13) - 8(a + 13) = 0 Or, (a - 8) (a + 13) = 0 So, 'a' = 8 or 'a' = - 13 But given that both are natural numbers, So, 'a' = 8 On putting value of 'a' in equation I, We get, 'b' = 20 - 8 = 12 Therefore, required product = 12 X 8 = 96

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