Question
Three numbers are in the ratio 5:9:12. The sum of the
largest and smallest of these numbers is 8500. What is the difference between the largest and smallest numbers?Solution
ATQ,
Let the smallest number be '5n'. So, the largest number = 5n X (12/5) = 12n ATQ, 5n + 12n = 8500 Or, 17n = 8500 So, 'n' = 500 Now, required difference = 12n - 5n = 7n = 7 × 500 = 3500
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