Question
Find the smallest number that, when divided by 3, 4, 5,
and 6, leaves a remainder of 2 but is divisible bySolution
LCM of 3, 4, 5, and 6 =60 ATQ- The number will be divided by 7 and divided by 3,4,5,6 leaves the remainder 2. 60×3+2=182.
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