Question
A man bequeaths Rs 25 lakh to a trust in the following
manner, 15% and the remaining amount is to be divided such that his wife, two daughters who receive equal shares, and three sons receive equal shares each. Daughter gets 1.5 times. If his wife gets twice the share that each daughter gets, what is his wife's share? (in lakh rupees)Solution
Remaining amount = Rs 25,000.00 x (100-15)/100 = 25,000.00Ă85/100 =2125000 Rs  Let the amount received by a daughter = x rupees Amount received by a son = Rs 1.5x And amount received by the wife = Rs 2x From the question, 2 daughters +1 wives+ 3 sons = 212500 2x+2x+4.5x =212500 8.5x =212500 X=212500/8.5 =250000 Share of wife =2x =2Ă250000 =500000Rs. Let the amount received by a daughter = x rupees Amount received by a son = Rs 1.5x And amount received by the wife = Rs 2x From the question, 2 daughters +1 wives+ 3 sons = 212500 2x+2x+4.5x =212500 8.5x =212500 X=212500/8.5 =250000 Share of wife =2x =2Ă250000 =500000Rs.
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