Question
A man bequeaths Rs 25 lakh to a trust in the following
manner, 15% and the remaining amount is to be divided such that his wife, two daughters who receive equal shares, and three sons receive equal shares each. Daughter gets 1.5 times. If his wife gets twice the share that each daughter gets, what is his wife's share? (in lakh rupees)Solution
Remaining amount = Rs 25,000.00 x (100-15)/100 = 25,000.00×85/100 =2125000 Rs  Let the amount received by a daughter = x rupees Amount received by a son = Rs 1.5x And amount received by the wife = Rs 2x From the question, 2 daughters +1 wives+ 3 sons = 212500 2x+2x+4.5x =212500 8.5x =212500 X=212500/8.5 =250000 Share of wife =2x =2×250000 =500000Rs. Let the amount received by a daughter = x rupees Amount received by a son = Rs 1.5x And amount received by the wife = Rs 2x From the question, 2 daughters +1 wives+ 3 sons = 212500 2x+2x+4.5x =212500 8.5x =212500 X=212500/8.5 =250000 Share of wife =2x =2×250000 =500000Rs.
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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