If 'N' is the greatest four digit number which when divided by 27, 6, 8 and 9 Leaves in each case the same remainder of 5, then the sum of the digits of 'N' is __________.
Solution –LCM of 27, 6, 8 and 9=216
Greatest number of 4 digit =9999
Dividing the largest four-digit number by the LCM of the given numbers
Remainder =63
Largest Divisible number of 4 digit by 216(27,6,8,9) =9999-63=9936
divided by 27, 6, 8 and 9 Leaves remainder 5 =9936+5=9941
now the sum of digits =9+9+4+1=23.
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