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Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 5) cm Difference between their perimeters = 4(a + 5) – 4a = 20 cm Therefore, perimeter of the rectangle = 2 × 20 = 40 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (10 + b) = 40 Or, 10 + b = 20 Or, b = 10 cm
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