Question
A vessel contains 80 litres of milk and water in the
ratio 3 : 1. If 20 litres of mixture is removed and replaced by pure water, then what will be the new quantity of milk in the vessel?Solution
Initial milk = (3/4) x 80 = 60 litres Initial water = (1/4) x 80 = 20 litres 20 litres removed from mixture: Milk removed = (3/4) x 20 = 15 litres Water removed = (1/4) x 20 = 5 litres Milk left = 60 - 15 = 45 litres Then 20 litres pure water added, so milk remains 45 litres
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