Question
A vessel contains 60 litres of milk and water in the
ratio 3 : 2. If 10 litres of the mixture is removed and replaced with pure water, then what will be the final ratio of milk to water?Solution
Initial milk = (3/5) x 60 = 36 litres Initial water = (2/5) x 60 = 24 litres 10 litres removed from mixture: Milk removed = (3/5) x 10 = 6 litres Water removed = (2/5) x 10 = 4 litres Milk left = 36 - 6 = 30 litres Water left = 24 - 4 = 20 litres Now 10 litres pure water added, so water becomes 20 + 10 = 30 litres Final ratio of milk to water = 30 : 30 = 1 : 1 Hence, the correct answer is 1 : 1.
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