Question
The ratio of the milk to water in a mixture is 9:4. 39
litres of mixture is taken out and 13 litres of water is added to the remaining mixture. If in the resultant mixture the quantity of milk is double the quantity of water, then find the quantity of water in the initial mixture.Solution
Let the quantity of the milk in the initial mixture = 9x litres
The quantity of the water in the initial mixture = 4x litres
The quantity of the milk in 39 litres of mixture = (39 / 13) Γ 9 = 27 litres
The quantity of the water in 39 litres of mixture = (39 / 13) Γ 4 = 12 litres
According to the question,
(9x β 27) = 2 Γ (4x β 12 + 13)
9x β 27 = 2 Γ (4x + 1)
9x β 27 = 8x + 2
x = 29
The quantity of the water in the initial mixture = 4 Γ 29 = 116 litres
13.99% of 299.99 Γ· 7.17 = ? Γ· 16.15
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
2 (1/4)% of 7999.58 + {49.06% of 898.87} + β143.14 β 19.99% of 1499.63 - (52 - 41) = ?
β1024.21 Γ β624.89 Γ· 4.98 + 11.99 Γ 4.01 = ?
?% of 1200.22 + 319.82 = 3.99 Γ 295.64
? 2 + (39.99 Γ 10.99 + 7.01) - (39.99 Γ 2.99 2 + 21.99) = 21.99 Γ 23.01
510.11 Γ· 16.98 Γ 5.14 β 119.9 = β?Β
Solve the given equation for ?. Find the approximate value.
(35.86 Γ 15.14) Γ· 9 + β(288.89) Γ 4.03 = ?
...24.75% of 20.125% of 30.05% of 2196.06 = ?Β
? + 163.99 β 103.01 = 24.01 Γ 6.98