Question
A 40-litre solution contains milk and water in the ratio
3 : 1. How many litres of water must be added so that the resulting mixture has milk and water in the ratio 3 : 2?Solution
ATQ, Total = 40 L, milk : water = 3 : 1 Milk = (3/4) × 40 = 30 L Water = (1/4) × 40 = 10 L Let x litres of water be added. New water = 10 + x, milk remains 30 L Given new ratio = 3 : 2 ⇒ 30 / (10 + x) = 3 / 2 Cross-multiply: 30 × 2 = 3(10 + x) 60 = 30 + 3x 3x = 30 ⇒ x = 10 L
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