Question
A mixture contains milk and water in the ratio 7:8,
respectively. If half of the mixture is replaced with 8 litres of water, then the resultant mixture will contain milk and water in the ratio 5:6, respectively. Find the original quantity of the mixture.Solution
Since, the ratio of the milk and water in the remaining mixture (when half of the mixture is taken out) will be same as initially. So, let quantity of milk and water in the remaining mixture be β7xβ litres and β8xβ litres, respectively. ATQ; 7x : (8x + 8) = 5 : 6 Or, 42x = 40x + 48 Or, 2x = 48 Or, x = 24 So, original quantity of mixture = (15 Γ 24) / 0.50 = 600 litres
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