Question
540 litres of mixture ‘A’ contains milk and water in
it. If mixture ‘A’ is mixed with 660 litres of mixture ‘B’ which contains water and salt, then the ratio of quantity of milk, water and salt in the final mixture will be 6:7:2, respectively. Find the difference between quantity of water in mixture ‘A’ and mixture ‘B’.Solution
Total quantity of mixture = 540 + 660 = 1200 litres Quantity of milk in final mixture = (6/15) × 1200 = 480 litres Quantity of water in mixture ‘A’ = 540 − 480 = 60 litres Quantity of salt in mixture ‘B’ = (2/15) × 1200 = 160 litres Quantity of water in mixture ‘B’ = 660 − 160 = 500 litres Required difference = 500 − 60 = 440 litres
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