Question
Mixture βAβ contains 70% acetone and rest 30 litres
water. Mixture βBβ contains 40 litres acetone and rest 50% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.Solution
Quantity of water in mixture βAβ = 30 litres Total quantity of mixture βAβ = 30/0.3 = 100 litres Therefore, quantity of acetone in mixture βAβ = 100 β 30 = 70 litres Quantity of acetone in mixture βBβ = 40 litres Total quantity of mixture βBβ = 40/0.50 = 80 litres Quantity of water in mixture βBβ = 80 β 40 = 40 litres Therefore, quantity of acetone in resultant mixture = 70 + 40 = 110 litres Quantity of water in resultant mixture = 30 + 40 = 70 litres Required ratio = 110:70 = 11:7
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