Question
Mixture ‘A’ contains 70% acetone and rest 30 litres
water. Mixture ‘B’ contains 40 litres acetone and rest 50% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.Solution
Quantity of water in mixture ‘A’ = 30 litres Total quantity of mixture ‘A’ = 30/0.3 = 100 litres Therefore, quantity of acetone in mixture ‘A’ = 100 – 30 = 70 litres Quantity of acetone in mixture ‘B’ = 40 litres Total quantity of mixture ‘B’ = 40/0.50 = 80 litres Quantity of water in mixture ‘B’ = 80 – 40 = 40 litres Therefore, quantity of acetone in resultant mixture = 70 + 40 = 110 litres Quantity of water in resultant mixture = 30 + 40 = 70 litres Required ratio = 110:70 = 11:7
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32 48 96 ? 720 2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
