Three Jar of equal volume contains milk mixed with

Solution

Let the volume of each jar be x litres. In the first jar, Ratio of milk and water = 2:1 Quantity of milk = x × 2/3 = 2x/3 Quantity of water = x × 1/3 = x/3 In the second jar, Ratio of milk and water = 2:3 Quantity of milk = x × 2/5 = 2x/5 Quantity of water = x × 3/5 = 3x/5 In the third jar, Ratio of milk and water = 4:5 Quantity of milk = x × 4/9 = 4x/9 Quantity of water = x × 5/9 = 5x/9 Now, Total quantity of milk = 2x/3 + 2x/5 + 4x/9 = x × [(30 + 18 + 20)/45] = 68x/45 Total quantity of water = x/3 + 3x/5 + 5x/9 = x × [(15 + 27 + 25)/45] = 67x/45 Required ratio of milk to water = 68x/45 : 67x/45 = 68:67 Hence, the ratio of milk and water in the large vessel is 68:67.