Question
A container contains 200 lit of pure milk and P liters
of water. Ratio of 25% of mixture to the initial quantity of water is 3 : 4 and when Q liters of water is added to it ratio of total mixture to water becomes 9 : 5. Then find the value of P + Q.Solution
(200 + P)/4P = 3/4
800 + 4P = 12P
P = 100 liters
And, (100 + Q)/(300 + Q) = 5/9
900 + 9Q = 1500 + 5Q
4Q = 600
Q = 150 liters
Required sum = 250
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