Question
Vessel A contains a mixture of milk and water, with 30
liters of milk. Vessel B also contains a milk-water mixture in the ratio of 5:4. The combined quantity of mixtures in vessels A and B is 140 liters, and the amount of water in vessel B is twice that in vessel A. Determine the quantity of mixture in vessel A.Solution
Milk in vessel A = 30 liters A + B = 140 liters Water in vessel B = 4x Milk in vessel B = 5x Water in vessel A = 4x/2 = 2x 30 + 2x + 4x + 5x = 140 11x = 110 x = 10 Water in vessel A = 2 * 10 = 20 liters Total quantity in vessel A = 20 + 30 = 50 liters Hence answer is option A
More Mixture Questions
[√441 ÷7] × 40% of ? = 500 – 12.5% of 400
√2025 + √1024 - √1296 = 20% of ?
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
- What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 63 × 4 = ?2 – 1620 ÷ 5
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
∛857375 + ∛91125 = ? + √6889
- What will come in place of the question mark (?) in the following questions?
0.5×120+25=? √3598 × √(230 ) ÷ √102= ?
