Question
The area of a circle is 1.54 cm2. Find the
perimeter of the minor sector that is subtended by an angle of 90o. (take Ď = 22/7)Solution
Area of circle = Ď X radius2
So, 1.54 = (22/7) X radius2
So, 0.49 = radius2
So, radius = 0.7 cm (Since radius cannot be negative, we may discard the negative value of root)
Perimeter of sector = 2 X radius of the circle + length of the arc
Length of minor arc = (θ/360o) X 2 X Ď X radius
So, length of the minor arc of the given circle = (90o/360o) X 2 X (22/7) X 0.7 = 1.1 cm
So, perimeter of the sector = 1.1 + (2 X 0.7) = 2.5 cm
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