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ATQ,
Let the length of each edge of the cube = ‘a’ cm
So, 6 × a² = 150
So, a² = 25
Or, a = 5 (Since, length cannot be negative, we take only the positive root)
So, length of the cuboid = 2 × a = 2 × 5 = 10 cm
Width of the cuboid = a = 5 cm
And, height of the cuboid = a = 5 cm
Desired area = 2 × (5 × 5 + 5 × 10 + 5 × 10) = 2 × 125 = 250 cm²
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