Question
Axar purchased several cubical boxes at Rs. 12 each and
placed them into a cuboidal box that perfectly fits these cubes. The curved surface area of the cuboidal box is 6.08 m², and its height is 80 cm. The length to breadth ratio of the cuboidal box is 11:8. If each cubical box has a side of 20 cm, determine the total cost Axar incurred to buy all the cubical boxes.Solution
ATQ, Let, length and breadth of cuboidal box be 11m cm and 8m cm, respectively. So, 2 × (11m + 8) × 80 = 6.08 × 10000 19m = 380, m = 20 Volume of cuboidal box = (220 × 160 × 80) cm3 Volume of each cubical box = (20 × 20 × 20) cm3 Required cost = {(220 × 160 × 80)/8000}× 12 = Rs.4224
More Mensuration Questions
30% of 800 - ?2 = 15
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
25% of 1000 + 10% of 150 – 22 × ? = 45
12.232 + 29.98% of 539.99 = ? × 5.99
- Evaluate: 196 ÷ 14 × 6 + 170 – 25% of 480
- What will come in place of the question mark (?) in the following questions?
7(1/7)% of 3500 + 6(2/3) % of 6000 = ? + 552.5
36.76 + 2894.713 + 34965.11 =?
15848 ÷ 4 – 793 × 6 + 3628 = 3 × ?
54% of 250 = 6 × 21 + √?
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