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    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 7:5, respectively and it has a perimeter of 48 metres. If a triangular piece with height of 8 metres and base of 10 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 100 Correct Answer Incorrect Answer
    B 110 Correct Answer Incorrect Answer
    C 120 Correct Answer Incorrect Answer
    D 130 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be ‘7x’ metres and ‘5x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (7x + 5x) = 24 x metres So, 24x = 48 So, x = (48/24) = 2 So, area of the entire paper = length × breadth = (7 × 2) × (5 × 2) = 14 × 10 = 140 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 8 × 10 = 40 m2 So, area of the remaining paper = 140 – 40 = 100 m2

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