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Let the length of the rectangular field be ‘l’ m Breadth of the rectangular field = (l – 11) m Therefore, perimeter of the rectangular field = 2 ×(l + l – 11) = (4l – 22) m According to the question, 4l – 22 = 350/5 Or, 4l = 70 + 22 Or, l = 92/4 = 23 metres
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