Question
If the lateral surface area of a
regular tetrahedron is 243√3 cm², find its volume.Solution
ATQ,
Let the edge length be 's' cm. The lateral surface area is given by:
Solving for 's' :
s² = 324
So, s = 18.
Volume of the tetrahedron :
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 27x² - 114x + 99 = 0
Equation 2: 18y² - 70y + 68 = 0
I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
I. x ² + 5 x + 6 = 0                Â
II. y²+ 7 y + 12= 0
...I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. 5x² -14x + 8 = 0 Â
II. 2y² + 17y + 36 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0