Question
The length of a rectangle is 8 metres more than its
width. If the perimeter of the rectangle is 64 metres then what is the area (in m2 ) of the rectangle?Solution
Let the width of the rectangle = ‘x’ metres Then, length of the rectangle = (x + 8) metres Perimeter of the rectangle = 2 × (length + width) Or, 2 × (x + x + 8) = 64 Or, 2x + 2x + 16 = 64 Or, 4x = 64 – 16 = 48 Or, x = 48/4 = 12 m So, area of the rectangle = x × (x + 8) = 12 × 20 = 240 m2
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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