Question
Sahil jogs 6 times around a square field whose each side
measures 16 metres. Mohan jogs 4.5 rounds around a rectangular field whose length is 30 metres and breadth is 30% less than its length. If the difference in the distance covered is ‘R’ metres, then find the value of (R + 8)(R - 14).Solution
Perimeter of square = 4 × side So, distance covered by Sahil in 1 round = 4 × 16 = 64 metres Length of rectangle = 30 metres Breadth = 0.70 × 30 = 21 metres So, perimeter of rectangle = 2 × (30 + 21) = 2 × 51 = 102 metres Distance covered by Mohan = 4.5 × 102 = 459 metres Distance covered by Sahil = 6 × 64 = 384 metres ATQ, R = 459 - 384 = 75 Therefore, required value = (75 + 8)(75 - 14) = 83 × 61 = 5,063
Find the simplified value of the given expression:
(125 - 75 ÷ 3 of 5) ÷ 2 + 4 of 12 ÷ 3 - 16 of 5 ÷ 20
1549.8 ÷ 8.2 + 65.6 × 55 = (? × 4) + (42 × 30.5)
420 ÷ 7 + 140 % of 20 + ? × 13 = 18 × 15
What will come in place of ‘?’ in the given expression :
? – (22 × 25 + 70% of 160) = 272
15 * 12 + 35% of 80 + 70% of 130 = ?
What is the value of (152+82) ÷17
(25.111 % of 200) × 26 ÷ 12.99 – 18.88 × 15.82 + 150.33% of 3√ 4917 = ? – 200
...12.5% of (100 + ?) = 40
(3984 ÷ 24) x (5862 ÷ 40) = ?
675 ÷ 15 + 225 – 18 × 6 = ?