Question
Sahil jogs 6 times around a square field whose each side
measures 16 metres. Mohan jogs 4.5 rounds around a rectangular field whose length is 30 metres and breadth is 30% less than its length. If the difference in the distance covered is ‘R’ metres, then find the value of (R + 8)(R - 14).Solution
Perimeter of square = 4 × side So, distance covered by Sahil in 1 round = 4 × 16 = 64 metres Length of rectangle = 30 metres Breadth = 0.70 × 30 = 21 metres So, perimeter of rectangle = 2 × (30 + 21) = 2 × 51 = 102 metres Distance covered by Mohan = 4.5 × 102 = 459 metres Distance covered by Sahil = 6 × 64 = 384 metres ATQ, R = 459 - 384 = 75 Therefore, required value = (75 + 8)(75 - 14) = 83 × 61 = 5,063
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
60.22 of 449.98% + 459.99 ÷ 23.18 = ?
88% of 1620 + 29² = ? + 1482 ÷ 18
(79.79% of 800.24 - √224.75) × (2/5 of 499.71) ÷ (10% of 600.26) = ?
Which of the following options is the closest approximate value which will come in place of question mark (?) in the following equation?
26.52 ×...
(108.999)² - (102.001)²=?
44.87% of (39.85 × ?) – 1520.88 0.51 = 1400.8
(8.86)² × (15.01)² ÷ √624.99 = 9?
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)