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Using formula Area = lb, Let the length of rectangular hall = x metre Therefore, Breadth = (8x/25) metre Area of rectangle = Length x Breadth ⇒ (8x/25) × x ⇒ 8x2/25 m2 According to question, ⇒ 8x2/25 = 200 Therefore, x2 = (200 x 25)/8 or, x = √{(200 x 25)/8} = 25 m Therefore, Length = 25 m and Breadth = 8 m Therefore, required difference = 25 – 8 = 17 m
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
36 x 3.6 ÷ 0.5 ÷ ? = 64
360 ÷ 9 + 15 % of 200 + ? * 10 = 45 * √25
36 × 15 + 20% 1250 = ? + 296
(-251 × 21 × -12) ÷ ? = 158.13
29% of 400 + 66% of 1100 - 50% of 1200 = ?
350% of (450 / 1.5) = ?% of 4200
(13)2 + 6 × (19)2 – 312 × 4 = ?