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    Question

    A circular wire of diameter 28 cm is folded in the shape

    of a rectangle whose sides are in the ratio 6:5. Find the area enclosed by the rectangle.
    A 456 cm² Correct Answer Incorrect Answer
    B 904 cm² Correct Answer Incorrect Answer
    C 920 cm² Correct Answer Incorrect Answer
    D 480 cm² Correct Answer Incorrect Answer
    E 630 cm² Correct Answer Incorrect Answer

    Solution

    Using the formula, Area = lb & D = 2r and A = πr²   Radius of circular wire = 28/2 = 14 cm Circumference of wire = 2πr = 2 x (22/7) x 14 = 88 cm Let the length and breadth of rectangle be 6x & 5x cm respectively. Therefore, perimeter of rectangle = 2(6x + 5x) = 22x According to the question, 22x = 88 ⇒ x = 88/22 = 4 Therefore, length of rectangle = 6x = 6 x 4 = 24 cm Breadth of rectangle = 5x = 5 x 4 = 20 cm Area = 24 x 20 = 480 cm²

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