Question
An edge of a variable cube is increasing at the rate of
2 cm/s. How fast is the volume of the cube increasing when the edge is 12 cm long?Solution
Let x be the length of a side and V be the volume of the cube. Then, v = x3. dV/dt = 3x2 × dx/dt It is given that dx/dt = 2 cm/s dv/dt = 3x2(2) = 6x2 Thus, when x = 12 cm dv/dt = 6 (12)2 = 864 cm3/s
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