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      Question

      A solid metallic rectangular block of dimensions 112 cm

      Γ— 44 cm Γ— 25 cm is melted and recast into a cylinder of radius 35 cm. The curved surface area (in cmΒ²) of the cylinder is: (TakeΒ Ο€ Β = 22/7)
      A 7260 Correct Answer Incorrect Answer
      B 6600 Correct Answer Incorrect Answer
      C 7040 Correct Answer Incorrect Answer
      D 6160 Correct Answer Incorrect Answer

      Solution

      Let the height of the cylinder be h According to the question, 112 Γ— 44 Γ— 25 = (22/7) Γ— 352 Γ— h β‡’ (112 Γ— 44 Γ— 25 Γ— 7)/(22 Γ— 35 Γ— 35) = h β‡’ h = 32 So, the height of the cylinder = 32 cm Now, Curved surface area of the cylinder = 2 Γ— (22/7) Γ— 35 Γ— 32 β‡’ 44 Γ— 5 Γ— 32 β‡’ 7040 ∴ The curved surface area (in cm2) of the cylinder is 7040.

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