Question
The length of the rectangle is triple its breadth. If
the perimeter of the rectangle is 40 m, then find the area (in m2) of the rectangle.Solution
Let the breadth of the rectangle = x, so the length of the rectangle = 3x Perimeter = 2(l + b) 40 = 2(x + 3x) 20 = 4x x = 5 Breadth = 5 m, Length = 15 m So the area of the rectangle = 5 × 15 = 75 m2
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
