Question
A circular field, which covers an area of 1386 square
meters, is planned to be enclosed by a compound wall that rises to a height of 3 meters. The wall is designed to be thin, with its thickness considered negligible. Calculate the surface area of one side of this compound wall.Solution
Let the radius of the circular field = 'r' metres Then, area of the field = π X r2 = (22/7) X r2 = 1386 So, r2 = 1386 X (7/22) = 441 So, r = √441 = 21 {Since, radius cannot be negative} Circumference of the circular field = 2 X (22/7) X 21 = 132 metres So, surface area of one side of the compound wall = 2πr X height = 132 X 3 = 396 m2
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
Find the approximate value of Question mark(?). No need to find the exact value.
(34.95 × 7.03) ÷ 5 + 27.98% of 249.88 – √(80.81) = ?
...What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
9.89 x 4.99 + 2.01 x 49.89 = ?% of 299.69
What approximate value will replace the question mark (?) in the following?
29.99...
What will be the approximate value of the following questions.
(74.75% of 600.29 – 44.85% of 399.99) × (√224.95 ÷ 15.01) = ?
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
12.03 x 4.21 +19.95% of 300.05 =Â ?
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
Relevant for Exams:
