Question
The area of a square is 196 cm2 which is 68
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 196 cm2 Length of each side of the square = √196 = 14 cm Area of the rectangle = 196 + 68 = 264 cm2 Length of the rectangle = 10 + 14 = 24 cm So, area of rectangle = length × breadth = 24 × breadth = 264 cm2 So, breadth of the rectangle = 264/24 = 11 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (11 + 24) = 70 cm
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