Question
Length and breadth of a rectangular field is (x + 6) cm
and (x – 3) cm, respectively. If the cost of ploughing the field at a rate of Rs. 10 per cm² is Rs. 5000, then find the cost of fencing the field at a rate of Rs. 12 per cm.Solution
ATQ, Area of the field = 5000/10 = 500 cm² So, (x + 6)(x – 3) = 500 Or, x² + 3x – 500 = 0 Or, x² + 25x – 20x – 500 = 0 Or, x(x + 25) – 20(x + 25) = 0 Or, (x + 25)(x – 20) = 0 So, x = 20 Perimeter of the field = 2 × {(20 + 6) + (20 – 3)} = 86 metres Desired cost = 86 × 12 = Rs. 1032
If (x + y) = 35, then find the value of (x - 10)6 + (y - 25)6.
 Solve: 5 – 3x > 2x + 10
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If √d + (1/√d) = 6, then find the value of d + (1/d).
if x2 – 2x + 1 = 0, then find the value of (x7 + x5 + x4 + x2)/x ?
If x = 15
find x 5 - 16 x 4 + 16 x 3 - 16 x 2 + 16 x  - 16 = ?
Find the number of zeroes in 16 × 75 × 40 × 125.
If (a + b) = 10 and ab = 21, find the value of (a² + b²).
What will come in place of the question mark (?) in the following series?
23, 46, ?, 184, 368, 736
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