Question
On a rectangular wall of length 22 metres and height 19
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 10 metres and length of altitude of the triangle is 3 metres, then excluding the window, what is the surface area (in m2) of the wall?Solution
Surface area of the entire wall = length × height = 22 × 19 = 418 m2 Surface area of the window = Sum of surface area of the square part + surface area of the triangular part = 102 + (1/2) × 10 × 3 = 100 + 15 = 115 m2 So, desired surface area = 418 – 115 = 303 m2
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 7p + 8q = 80
II. 9p – 5q = 57
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. (4x-5)3Â +Â 1/(4x-5)3Â = 2
II. 2[(y+1/y)2- 2]- 9(y+1/y)= -14
If 3x – 2y = 10 and xy = 11, the value of 27x³ – 8y³ is __________.
I. 9x2 + 45x + 26 = 0
II. 7y2 – 59y − 36 = 0
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
