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    Question

    The angle of elevation of the top of a tower from a

    point on ground which is 30 mtrs. away from the foot of the tower is 30Β°. Height of the tower is: 1.10/ √3 mtrs 2.10 Γ— √3 mtrs 3.100 mtrs 4.20meter.
    A 2 Correct Answer Incorrect Answer
    B 3 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer
    D 1 Correct Answer Incorrect Answer

    Solution

    Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC. In Ξ”ABC, trigonometric ratio involving AB, BC and ∠C is tan ΞΈ. tan C = AB/BC tan 30Β° = AB/30 1/√3 = AB/30 AB = 30/√3 = (30 Γ— √3) / (√3 Γ— √3) = (30√3)/3 = 10√3 Height of tower AB = 10√3 m.

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