Question
The angle of elevation of the top of a tower from a
point on ground which is 30 mtrs. away from the foot of the tower is 30Β°. Height of the tower is: 1.10/ β3 mtrs 2.10 Γ β3 mtrs 3.100 mtrs 4.20meter.Solution
Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC. In ΞABC, trigonometric ratio involving AB, BC and β C is tan ΞΈ. tan C = AB/BC tan 30Β° = AB/30 1/β3 = AB/30 AB = 30/β3 = (30 Γ β3) / (β3 Γ β3) = (30β3)/3 = 10β3 Height of tower AB = 10β3 m.
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