Question
The angle of elevation of the top of a tower from a
point on ground which is 30 mtrs. away from the foot of the tower is 30°. Height of the tower is: 1.10/ √3 mtrs 2.10 × √3 mtrs 3.100 mtrs 4.20meter.Solution
Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC. In ΔABC, trigonometric ratio involving AB, BC and ∠C is tan θ. tan C = AB/BC tan 30° = AB/30 1/√3 = AB/30 AB = 30/√3 = (30 × √3) / (√3 × √3) = (30√3)/3 = 10√3 Height of tower AB = 10√3 m.
Choose the alternative which is closely resembles the water-image of the given combination.
Choose the alternatives which is closely resembles the water image of the given combination.
Choose the alternatives which is closely resembles the water image of the given combination.
Select the figure that is the correct water image of the given figure (water is along MN).
Select the water image of the given figure.
What is water image of given figure?
Choose the alternative which is closely resembles the water-image of the given combination.Â
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