Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 10 years hence from now will be 5 times of A's age, 20 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 10) = 5 x (3x - 20) Or, 5x + 10 = 15x - 100 Or, 10x = 110 x = 11 So, present age of 'A' = 3 x 11 = 33 years
LCM of 'x' and 'y' is 30 and their HCF is 1 such that {10 > x > y > 1}.
I. 2p²- (x + y) p + 3y = 0
II. 2q² + (9x + 2) = (3x + y) q
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
If the roots of the quadratic equation 6m² + 7m + 8 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. x2 + 13x + 42 = 0
II. y² + 13y + 40 = 0
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root o...
I. 8x2 - 2x – 15 = 0
II. 12y2 - 17y – 40 = 0
