Question
A metallic sphere of radius 4.2 cms. Is melted and
recast into the shape of a cylinder of radius 6 cms. Height of the resultant cylinder would be:Solution
As a metallic sphere is melted and recast into the shape of a cylinder, their volume must be the same. Volume of the sphere = Volume of the cylinder Let us find the volume of the sphere and cylinder by using formulae; Volume of the sphere = 4/3Οr3 where r is the radius of the sphere Volume of the cylinder = Οr2h where r and h are radius and height of the cylinder respectively Radius of the sphere, rβ = 4.2 cm Radius of the cylinder, rβ = 6 cm Let the height of the cylinder be h. Volume of sphere = Volume of cylinder 4/3Οrβ3 = Οrβ2h (4/3)rβ3 = rβ2h h = 4rβ3 / 3rβ2 = (4 Γ 4.2 cm Γ 4.2 cm Γ 4.2 cm) / (3 Γ 6 cm Γ 6 cm) = 2.744 cm Hence, the height of the cylinder so formed will be 2.744 cm.
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