Question
The present ages of A and B are 'x' years and 'y' years
respectively. Four years ago, the sum of their ages was 34 years. If the average of 'x' and 31 is 4 more than the average of 'y' and 31, then what will be the age of A three years from now?Solution
ATQ,
x + y = 34 + 4 + 4 Or, x + y = 42 ------ (I) (x + 31) ÷ 2 = (y + 31) ÷ 2 + 4 Or, x + 31 = y + 31 + 8 Or, x = y + 8 On putting value of 'x' in equation I, We get, y + 8 + y = 42 Or, 2y = 34 Or, 'y' = 17 On putting value of 'y' in equation I, We get, 'x' = 17 + 8 = 25 Therefore, required age = 25 + 3 = 28 years
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