Question
An army of 2100 men has provision for 50 days. After 10
days due to injuries some of them left and the food were now enough for next 50 days for remaining men. The number of men left is:Solution
As initially there was provision of food for 50 days for 2100 men, Initial quantity of food = 2100 × 50 = 105000 units. Food consumed in 10 days = 2100 × 10 = 21000 units Food remained after 10 days = 105000 – 21000 = 84000 units. Now, 84000 units of food is sufficient for 50 days for remaining men ⇒ Number of remaining men = 84000/50 = 1680 ∴ The number of men left = 2100 – 1680 = 420
In the question assuming the given statements to be true, find which of the conclusion(s) among given three conclusions is/are definitely follows and t...
Statement: P ≤ W < O = D ≥ G > T
Conclusions:
I. P ≤ T
II. W < D
Statement: X≤Y<W =Z ≤U<S;S>T ≥V
I. Z≥T
II. Z > X
Statements : C © S * R, U % R $ ZÂ
Conclusions :Â
I. Z $ CÂ
II. U % SÂ
III. U © C
Statements: N = Q < X ≤ L, L > T = G ≥ E
Conclusions:
I. L ≥ Q
II. G > X
III. L > N
Statements: U > H ≥ W; S > T ≥ B; S < H; C ≤ D = U
Conclusions:
I. D > B
II. T < U
III. W ≤ D
Statements: B < C ≥ D; T < G ≥ E; E < C
Conclusions:
I. T < C
II. C > G
III. E < D
In this question, the relation between various elements is shown in the statement. After the statement, two conclusions are given, select a suitable op...
Statements: P # Q @ R & S $ T # W % I, K $ S @ L
Conclusions: I. K # I II. P & T
...Statements : Z < S < W < D; E ≤ C ≤ Y < D; U < T < S ≤ V
Conclusions :
I. V > Z
II. C < U
III. V > E
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