Radius and height of a right circular cone are 36 cm and

Solution

PD = 48 - 12 - 16 = 20 cm
∆APQ ~ ∆ABC (by AA similarity)
So, (PQ/BC) = (AP/AB)
Or, PQ = (12/48) × 36 = 9 cm
Again, ∆ADE ~ ∆ABC (by AA similarity)
So, (DE/BC) = (AD/AB)
Or, DE = (32/48) × 36 = 24 cm
Volume of uppermost part = (1/3) × 3 × 9² × 12 = 972 cm³
Volume of middle part = (1/3) × 3 × 24² × 32 - (1/3) × 3 × 9² × 12
= 18432 - 972 = 17460 cm³
Volume of lowermost part = (1/3) × 3 × 36² × 48 - (1/3) × 3 × 24² × 32
= 62208 - 18432 = 43776 cm³
Required ratio = 972:17460:43776 = 27:485:1216