Question
The circumference of two circles are 132 cm and 88 cm
respectively. What is the difference between the area of the larger circle and the smaller circle?Solution
Circumference of larger circle = 2πr 132 = 2 × 22/7 × r r = (132 × 7)/(22 × 2) = 21 cm. Area of a larger circle = πr² = 22/7 × 21 × 21 = 1386 cm. Circumference of smaller circle = 2πr 88 = 2 × 22/7 × r r = (88 × 7)/(22 ×2) = 14 cm. Area of a smaller circle = πr² = 22/7 × 14 × 14 = 616 cm. ∴ Required difference = 1386 – 616 = 770 cm.
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 81x - 117√x + 40 = 0
II. 81y - 225√y + 136 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 2 x ² + x  – 1 = 0                Â
II. 2 y ² - 3 y + 1 = 0
...- What should be the value of t in the equation x² + tx + 64 = 0 so that it has two equal real roots?
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
l). p² - 26p + 153 = 0
ll). q² - 17q + 72 = 0
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