Question
I. p2 – 5p + 6 =
0                  II. 36q2 = 81 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if; (1) p = q or relationship cannot be established between p and q (2) p > q (3) p < q (4) p ≤  q (5) p  ≥ qÂSolution
I. p2 – 5p + 6 = 0  ⟹ p2 – 2p – 3p +6 = 0                        ⟹ p (p - 2) – 3(p - 2) = 0 ⟹ (p - 3)(p - 2) = 0                             ⟹ p = 3, 2 II.36q2 = 81 ⟹ (6 q)2 = 92 ⟹ q =  ± 3/2  Hence, p > q
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