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I. p2 – 5p + 6 = 0 ⟹ p2 – 2p – 3p +6 = 0 ⟹ p (p - 2) – 3(p - 2) = 0 ⟹ (p - 3)(p - 2) = 0 ⟹ p = 3, 2 II.36q2 = 81 ⟹ (6 q)2 = 92 ⟹ q = ± 3/2 Hence, p > q
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